The formula for sodium iodide is NaI.1. How many GRAMS of sodium iodide are present in 6.07E+21 formula units of this compound ? _____ grams2. How many formula units of sodium iodide are present in 9.54 grams of this compound ? _____ formula units
NaIMass of NaI = 23 + 126.9= 149.9a)6.022 x 10^23 unit contains 149.9 gHence 6.07 x 10^21 = (149.9*6.01 x 10^21)/6.022 x 10^23= 1.51 gram b)149.9 gram contains 6.022 x 10^23 unitsHence 9.54…
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