Sam heaves a bowling ball with weight 16-lb straight upward, giving it a constant upward acceleration from rest of 44.2 m/s^2 for a height 68.0cm . He releases it at height 2.29 m above the ground. You may ignore air resistance.What is the speed of the bowling ball when he releases it?How high above the ground does it go?How much time does he have to get out of its way before it returns to the height of the top of his head, a distance 1.80m above the ground?
As the ball is released from rest, speed, u = 0 m/sHeight for which it is raised, s = 68 cm or 0.68 mAcceleration, a = 44.2 ms-2Final velocity at 68 cm heightThird equation of motionv2 = u2 +…
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