I’m very confused. A sample of 1.00 L of gas at NTP conditions contains 20% oxygen and 80% nitrogen. Calculate the number of moles of each gas.

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October 1, 2020
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Could anyone help me with this. I’m very confused.

4. A sample of 1.00 L of gas at NTP conditions contains 20% oxygen and 80% nitrogen. Calculate the number of moles of each gas. Below are my calculations, but they don’t match other answers. I don’t know what I did wrong.

1.00 L / 22.4 L/mol = 0.04464 moles

.04464 /5 = .008928 per 20%

20% = .008928 mole

80% = .008928 x 4 = .03571 mole

I’m very confused. A sample of 1.00 L of gas at NTP conditions contains 20% oxygen and 80% nitrogen. Calculate the number of moles of each gas.

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Which of the following statements is incorrect about benzene?

“The solubility of benzoic acid in water is 6.8 g/100 mL at 95C and 0.3 g/100 mL at 25C. You are given 10 g of benzoic acid.