Calculate the work done when 50.0g of tin dissolves in excess acid at 1.00atm and 25 (degree in celsius) Sn(s)+2H(aq)—– Sn(aq) +H2(g) Assume ideal gas behavior The work done = (pressure)*(increase in volume) The increase in volume is due to the H2 gas created. 50 g of tin (Sn) is 0.421 moles. That is also the number of moles of H2 that are created. Use tha ideal gas law to compute the added volume due to that gas.
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