An uncharged capacitor is connected to the terminals of a 4.0V battery, and 12mu*C flows to the positive plate. The 4.0V battery is then disconnected and replaced with a 7.0V battery, with the positive and negative terminals connected in the same manner as before. How much additional charge flows to the positive plate?q=________mu*C
Answer to 7033568 Q = CVC = Q/V = 12×10^-6/4 = 2μFΔQ = CΔV = (2×10^-6)(7) = 14 μC
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